Last updated at Aug. 3, 2021 by Teachoo

Transcript

Ex 5.2, 17 Find the 20th term from the last term of the A.P. 3, 8, 13, …, 253 Given AP 3, 8, 13, …, 253 Now, 20th term from last term of AP 3, 8, 13, …, = 20th term of AP 253, 248, 243, …., 8, 3 Thus, our AP is 253, 248, 243, …., 8, 3 Here a = 253 d = 248 – 253 = −5 We need to find 20th term n = 20 Now, an = a + (n – 1) d Putting values an = 253 + (20 – 1) × (−5) an = 253 + 19 × (−5) an = 253 − 95 an = 158 So the 20th term from the Last is 158

Ex 5.2

Ex 5.2, 1

Ex 5.2, 2 (i) (MCQ)

Ex 5.2, 2 (ii) (MCQ) Important

Ex 5.2, 3 (i)

Ex 5.2, 3 (ii)

Ex 5.2, 3 (iii) Important

Ex 5.2, 3 (iv)

Ex 5.2, 3 (v) Important

Ex 5.2, 4

Ex 5.2, 5 (i)

Ex 5.2, 5 (ii) Important

Ex 5.2, 6 Important

Ex 5.2, 7

Ex 5.2, 8

Ex 5.2, 9

Ex 5.2, 10

Ex 5.2, 11

Ex 5.2, 12 Important

Ex 5.2, 13 Important

Ex 5.2, 14 Important

Ex 5.2, 15

Ex 5.2, 16

Ex 5.2, 17 Important You are here

Ex 5.2, 18

Ex 5.2, 19

Ex 5.2, 20 Important

Chapter 5 Class 10 Arithmetic Progressions (Term 2)

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.